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TRANSFORM

Returns an array by applying <function> on each element of <array>.

The Lambda function <function> is a mandatory parameter.

Syntax

TRANSFORM(<function>, <array>)

Parameters

Parameter Description Supported input type
<function> A Lambda function used to check elements in the array. Any Lambda function
<array> The array to be transformed by the function. Any array

Return Type

ARRAY of the same type as the input array

Examples

SELECT
	TRANSFORM(x -> x * 2, [ 1, 2, 3, 9 ] ) AS levels;

Returns: 2,4,6,18

In the example below, the TRANSFORM function is used to CAST each element from a string to a date type. With each element now as a date type, the INTERVAL function is then used to add 5 years to each.

SELECT
    TRANSFORM(x ->  CAST(x as DATE) + INTERVAL '5 year',
        [ '1979-01-01', '1986-02-26', '1975-04-04' ] )
    AS registeredon;

Returns: ["1984-01-01 05:06:00","1991-02-26 05:06:00","1980-04-03 05:06:00"]

In the example below, TRANSFORM is used with CASE to modify specific elements based on a condition.

SELECT
    TRANSFORM(x, y -> CASE
        WHEN y = 'esimpson' THEN x
        ELSE 0
        END,
        [ 1, 2, 3 ],
        [ 'kennethpark', 'esimpson', 'sabrina21' ] )
    AS levels;

Returns: [0,2,0]

This example again uses TRANSFORM with CASE. Elements that don’t meet the condition are left unchanged.

SELECT
    TRANSFORM(x, y -> CASE
        WHEN y % 2 == 0
        THEN UPPER(x)
        ELSE x END,
        [ 'esimpson', 'sabrina21', 'kennethpark' ],
        [ 1, 2, 3 ] )
    AS players;

Returns: ["esimpson","SABRINA21","kennethpark"]

This is another example using CASE that changes elements only if they meet the condition.

SELECT
    TRANSFORM(x, y -> CASE
        WHEN x < y THEN y
        ELSE x END,
        [ 100, 700, 800 ],
        [ 300, 500, 200 ] )
    AS res;

Returns: [300,700,800]